The letters in the word FRONDS are permuted in all possible ways and arranged in the alphabetical order. Find the word at position 47 in the permuted alphabetical order
A. DOFNSR
B. DNSROF
C. DOFNRS
D. DNSRFO

• the first word= 'DFNORS'
  so by keeping 'DF' cons. arrange other letters i.e NORS so no of ways =4!=24
  now keep 'DN' cons arrange other letters i.e 'FORS' so no of ways =4!=24
  and the total no of ways =24+24=48
  the 48 position word will be 'DNSROF'
  as it is alphabetical order
  so the 47 position word will be 'DNSRFO'
  ans-D
• 10 years agoHelpfull: Yes(38) No(3)
• 1st word is DFNORS
  DF****=4!=24 ways
  DN****=4!=24 ways
  then 48th word is DNSROF
  hence 47th word id DNSRFO
  so answer D is correct..
• 10 years agoHelpfull: Yes(5) No(1)
• Df****=24 ways
  Do****=24 ways
  then total no of way this is 48 no is DNSRFO then the 47 no is DNSROF
  
• 10 years agoHelpfull: Yes(2) No(7)
• in FRONDS, total letters are=6, at 2nd place the letter is R, originally after R comes S, here S is at 6th position i.e. 3 places from R. By hit and trial method only option D satisfies this condition.
  ans-D
• 10 years agoHelpfull: Yes(1) No(1)
• c,,DOFNRS
  DF....=16 WAYS
  DN....=16 WAYS
  D0....=16 WAYS
  DOFNRS=47TH and DOFNSR=48TH
  
• 10 years agoHelpfull: Yes(0) No(4)