find the number of consecutive zeroes at the end of 100!*200!*300!

• 147
  
  there is a property for such type of questions
  like if u have to find no. of zeroes in 100!
  
  100/5=20(integer part) + 100/sq(5)=4(integer part) so 24 zeroes in 100!
  
  similarly for 200!
  200/5=40 + 200/25=8 + 200/125=1 so 49 zeroes in 200!
  
  nd for 300!
  300/5=60 + 300/25=12 + 300/125=2 so 74 zeroes
  
  by multiplying all...we will sum all zeroes so 147 is answer!!
• 11 years agoHelpfull: Yes(1) No(0)
• Can anybody answer this how many cosecutive zeroes in 100!+200!?
  I have solved it as 100! Has 24 zeros and 200! Has 49 zeros at last I added them the answer will be 73 but in the book it is given 24..how?
  
• 10 years agoHelpfull: Yes(0) No(0)