Consider an infinite geometric series with the first term a and common ratio r. If its sum is 4 and the second term is 3/4 then (a,r) has the value,
(a). (7/4,3/7)
(b). (2,3/8)
(c). (3/2,1/2)
(d). (3,1/4)

• we know that sum of infinite series is a/(1-r)..here sum is given as 4
  in GP if first term is a then 2nd term will be ar
  given that ar=3/4 & a/(1-r)=4 after solving both eqtn we will get a=3 and r=1/4
  so answer d (3,1/4)is correct
• 10 years agoHelpfull: Yes(1) No(0)
• given a/1-r=4 & ar=3/4
  after solving for r, r=3/4 & 1/4
  corresponding values of a are 1 & 3
  -1
• 10 years agoHelpfull: Yes(1) No(0)
• for an infinite g.p.... r must be
• 10 years agoHelpfull: Yes(0) No(1)
• (d) option is correct
• 7 years agoHelpfull: Yes(0) No(0)