IIT-JEE
Exam
For all complex numbers z1,z2 satisfying |z1|=12 and |z2-3-4i|=5,the minimum value of |z1-z2| is,
(a). 0
(b). 2
(c). 7
(d). 17
Read Solution (Total 1)
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- |z1|=12 is a circle of radius 12 unit.
where |z2-3-4i|=5 is a circle of radius 5. whose centre shifted to (3+4i) i.e. 5 unit away from origin.
|z1-z2| is minimum distance between these circles which is 2 unit. - 11 years agoHelpfull: Yes(0) No(0)
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