IIT-JEE
Exam
For all complex numbers z1,z2 satisfying |z1|=12 and |z2-3-4i|=5,the minimum value of |z1-z2| is,
(a). 0
(b). 2
(c). 7
(d). 17
Read Solution (Total 1)
-
- |z1|=12 is a circle of radius 12 unit.
where |z2-3-4i|=5 is a circle of radius 5. whose centre shifted to (3+4i) i.e. 5 unit away from origin.
|z1-z2| is minimum distance between these circles which is 2 unit. - 10 years agoHelpfull: Yes(0) No(0)
IIT-JEE Other Question
Which of the following pieces of data does not uniquely determine an acute angled triangle ABC(R=circumradius)?
(a). a,sinA,sinB
(b). a,b,c
(c). a,sinB,R
(d). a,sinA,R
The domain of definition of the function y(x) given by 2^x+2^y=2 is,
(a). (0,1]
(b). [0,1]
(c). (-infinite,0]
(d). (-infinite,1)