question was like:: there is side of a hexagon given(6 root 2)... it was said that joining the mid points of each side another hexagon was created... what was the difference between the areas of two hexagon(express as %)....dont remember the option...i marked 25 percent as answer....

• AREA outer hexagon =6*((root 3)/4)*(6 root 2)2
  firstly we will calculate inner hexagon side=root of ((3 root 2)2+ (3 root2)2)=6
  area of inner hexagon=6*((root 3)/4)*(6)2
  diiference b/w the areas of two hexagon(express as %)=((AREA-area)*100)/AREA %
  =50 %
• 11 years agoHelpfull: Yes(11) No(13)
• 25% is right answer
  difference of area is 27 squrt3
  and total area is 108squrt3
  hence 25%
• 11 years agoHelpfull: Yes(8) No(6)
• chopped the hexagon into 24 equal triangle of which 18 compose the smaller hexagon, making the ratio of the areas 18/24 = 3/4, with 1/4 of the original area cut off. (First join the midpoints to the center of the hexagon to obtain 6 equilateral triangles. In each of these, join the center with the vertices. On the right you see the minimal configuration that explains the solution.
• 11 years agoHelpfull: Yes(3) No(3)
• Area of big hexagon is (12roo3/8)a^2
  Area of small Hexagon is (9root3/8)a^2
  so diff. is 25%
• 11 years agoHelpfull: Yes(3) No(2)
• could u please ur answer ?
• 11 years agoHelpfull: Yes(1) No(1)
• how can we find the sides of internal hexagon ?
• 11 years agoHelpfull: Yes(1) No(0)
• wudnt it be 50% ??
• 11 years agoHelpfull: Yes(1) No(1)
• ans is- 25%...
  
  area of hexagon = 3root3 *s^2/2..
  
  so area of original hexagon is =108root3.
  area of new hexagon formed by joining mid points = 27 root 3
  diff in area in %= 25%
• 11 years agoHelpfull: Yes(1) No(0)
• inner hexagon is 37.5% of bigger hexagon if it is regular
  or difference b/w the areas of 2 hexagon is 12.5% of bigger hexagon and 33.33% of inner hexagon
• 11 years agoHelpfull: Yes(1) No(1)
• 25% is the wright answere
  area of hexagon is (3*root3by2)*side^2
  distance btwn centre and vertices be same as side 6root2
  
• 10 years agoHelpfull: Yes(0) No(1)
• A regular hexagon contains 6 equilateral triangles of same area
  so..side of inner trinangle is 6root2*cos 30 i.e (6.root3)/root2
  so area ratio will be square of sides i.e (6*root3/root2*6*root2)^2 i.e ( root3/2)^2 i.e 3/4
  
  
• 9 years agoHelpfull: Yes(0) No(0)
• ratio of bigger to smaler is 4:3
  so (4-3)/4 = 25%
• 9 years agoHelpfull: Yes(0) No(0)
• correct answer will be 50%
  as area of hexagon is 3pow(1%3)*side pow(2)%2
• 9 years agoHelpfull: Yes(0) No(0)