A fair coin is tossed independently four times. The probability of the event “the
number of time heads shown up is more than the number of times tails shown up”
is
(a).1/16
(b).1/8
(c).1/4
(d).5/16

• total no. of outcomes=2*2*2*2=>16
  chances to come head=1/2+1/2+1/2+1/2=>2
  maximum chances to getting heads will be 2/16=1/8
  so answer will be option (b)
• 10 years agoHelpfull: Yes(2) No(2)
• sample space is 2^4=16.
  favourable cases=5 i.e. HHHH,HHHT,HHTH,HTHH,THHH.
  SO, p=5/16.
  ans= (d).
• 10 years agoHelpfull: Yes(1) No(0)
• Possibilities for no Heads > no Tails
  => {(HHHT),(HHHH),(HTHH),(THHH),(HHTH)}=5
  Total no possibilities of is 2^4 =16
  So Ans will be 5/16
• 10 years agoHelpfull: Yes(0) No(1)