IES EC
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Q. A magnetic drum of 8 inch diameter has 100 tracks and storage density of 200 bits/inch. What is its storage capacity?
Option
a) 8402 bits
b) 202400 bits
c) 502400 bits
d) 1004800 bits
Read Solution (Total 1)
-
- storage capacity = pi * diameter * tracks * storage density
= 3.14 * 8 * 100 * 200
= 502400 bits - 7 years agoHelpfull: Yes(0) No(0)
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