Find the maximum value of n such that 157 is perfectly divisible by 12 n

@shradha - see 12 = 2*2*3 . therefor we get 75 when we divide by d factorials of 3. now dividing by d factorials of 2 we get.
157/2+157/4+157/8+157/16+157/32+157/64+157/128 = 152
now to find the solutions of this type of problem we need to take min(152,75)
and i.e 75 . that's y 75 is the correct answer.
again if you have 18^n = then 18 = 3*3*2 . again you have to check for both 2 and 3. and the minimum wil be the answer,
Got It ?? :) :) :)
10 years agoHelpfull: Yes(5) No(2)
@ ashutosh anshu if there is 18^n or 12600^n in place of 12^n..then what is the solution? actually i want to know why u use 3 instead of 2 or why u didnt use both 2 and 3?
10 years agoHelpfull: Yes(3) No(0)
what if 157! is perfectly divisible by 18^n
7 years agoHelpfull: Yes(0) No(0)

Find the maximum value of n such that 157! is perfectly divisible by 12^n