find the no of ways in which 210 be expressed as a product of 3 distinct factors?

• the factor of 21o is 7,3,10
  we can arrange these numbers 3! ways. that is 6
• 11 years agoHelpfull: Yes(21) No(7)
• 210=2*3*5*7;
  so it can be expressed as in 3c2 i.e. in 6 ways
  1)2*3*35
  2)2*5*21
  3)2*7*15
  4)3*5*14
  5)3*7*10
  6)5*7*3
  
  
• 11 years agoHelpfull: Yes(18) No(5)
• 210 can be express as 2*3*5*7 combine any two number as a single group then 4c2=12, and combination of three number 3! total way=12*6=72
• 11 years agoHelpfull: Yes(2) No(7)
• 210=2*3*5*7
  the possible combinations of 3 distinct factors are
  2 3 35
  2 5 21
  2 7 15
  3 5 14
  3 7 10
  5 7 6
  so total 6 ways are there...
• 11 years agoHelpfull: Yes(1) No(2)
• the factors are 3,7,2,5.now we have to take 3 factors.this means any two of them and the third a combination of the rest two.so it will be 3!x4c2=36
• 11 years agoHelpfull: Yes(1) No(1)
• 210=1*2*3*5*7
  total 5 factors so distinct factors =5c3=10 ways
  
• 11 years agoHelpfull: Yes(1) No(0)
• ans is 6 ways
  
  210 has 4 prime factors as follows
  210 = 2 * 3 * 5 * 7
  
  we want 3 distinct factors(not necessorily prime)
  hence select 2 from 4 :
  4C2 = 4*3 = 12
  
  multiplication of remaining 2. hence divide ans by 2..
  hence 12/2 = 6.
  
  Ans is: 6
• 11 years agoHelpfull: Yes(0) No(7)
• 7*3*10=210
• 11 years agoHelpfull: Yes(0) No(4)
• Answer is 6 ways
• 11 years agoHelpfull: Yes(0) No(1)
• 3,7,10 that is 3*7*21=210 by using 3,7,10 numbers
• 11 years agoHelpfull: Yes(0) No(1)
• 10c3=120.The factors are 1,2,3,5,6,7,10,14,15,21.
  
• 11 years agoHelpfull: Yes(0) No(0)
• it must be 6 ways..
  2,3,5,7 are factors
  now products are
  6*5*7
  2*15*7
  2*3*35
  10*3*7
  14*3*5
  21*2*5
  
• 11 years agoHelpfull: Yes(0) No(0)
• 4 ways i think so...........
  
• 11 years agoHelpfull: Yes(0) No(0)
• it can be expressed in 3! ways.
• 11 years agoHelpfull: Yes(0) No(0)
• plz give the options
• 11 years agoHelpfull: Yes(0) No(0)
• factor of 210 is 7,3,10
  so 3! is 6 ways.
• 11 years agoHelpfull: Yes(0) No(0)
• 9
  1 with 3 combinations of 2,3,5,7 taking 2 at a time..
  1,2*3,5*7
  1,2*5,3*7
  1,2*7,3*5
  now 6 combinations of 2,3,5,7 making set of 1 no. and product of 2
  2,3,35
  2,5,21
  2,7,15
  3,5,14
  3,7,10
  5,7,6
• 11 years agoHelpfull: Yes(0) No(0)