15 women or 10 men complete in 55 days .how many days 4 women & 5 men will take

• 71.739 days
  1Woman,1Day work=1/(55*15),so 4Woman 1Day work=4/(55*15)
  1Man , 1Day work=1/(55*10),so 5Men 1Day work=5/(55*10)
  4 women & 5 men 1 Day work=[4/(55*15) + 5/(55*10)]=23/1650
  So days to complete the work=1650/23=71 17/23 or 71.739
• 11 years agoHelpfull: Yes(29) No(2)
• 1 woman,1 day work=1/55*15
  1 man,1 day work=1/55*10
  4 woman+5 men,1 day work=4/(55*15) + 5/(55*10)=23/1650
  thus answer=1650/23 days
• 11 years agoHelpfull: Yes(12) No(0)
• in 412.5 days i think s.o
• 11 years agoHelpfull: Yes(5) No(10)
• ans= 71.739 days = 71 & 17/23 days
  15 women work = 10 men work
  1 woman work = 3/2 men work
  15 women complete = in 55 days
  1 woman will compllete = 55*15=825
  (4 women + 5 men)=> 4 + 5*3/2 => 23/2 women will complete = 825/(23/2)
  = 825*2/23
  = 71.739
  = 71 and 17/23 days
• 11 years agoHelpfull: Yes(3) No(4)
• 71.739 days..
  
  bcoz w=1/(55*15) and m=1/(55*10)
  
  4w+5m=1/71.739
• 11 years agoHelpfull: Yes(2) No(1)
• 55/((4/15)+(5/10))=71.739127
• 11 years agoHelpfull: Yes(2) No(0)
• 4/55+1/11=9/55
  
  so,it v'll take 55/9 days
• 11 years agoHelpfull: Yes(1) No(5)
• 72 days(approx)
  1 men one day work=1/15*55=1/825
  1 women one day work=1/10*55=1/550
  5men and 4 women combine together time taken=1/[(5/550)+(4/825)] =71.74=72days(approx)
• 11 years agoHelpfull: Yes(1) No(1)
• 15 womens complete work in 55 days
  10 men complete work in 55 days,
  so one women can do 1/(55*15) of work each day,
  and similarly one men can do 1/(55*10) of work each day,
  and finally 4 women & 5 men can do
  4*1/(55*15)+5* 1/(55*10) of work daily,
  so total no of days will be reciprocal of answer,
  
  
• 11 years agoHelpfull: Yes(1) No(0)
• 1 women's 1 days work = 1/(55*15)
  1 man's 1 days work = 1/(55*10)
  thus 4 women & 5 men 1 day work = 4/(55*15) + 5/(55*10) =23/1650
  no of days= 1650/23 =71.73
• 11 years agoHelpfull: Yes(1) No(0)
• ans=15*10*55/(4*10)+(15*5)=15*10*55/115=1650/23=71.729 days
  
• 11 years agoHelpfull: Yes(1) No(0)
• no of days =total days/((and/0r)+(and/or))
  =55/(4/15+5/10)
  =55/(23/30)
  =55*30/23
  =1650/23
  =71.74
  =78(approx)days
• 11 years agoHelpfull: Yes(0) No(0)
• 4 woman-1 day- 4/(55*15)
  5 man-1 day-5/(10*15)
  therefore,4w&5m do (4/(55*15)+5/(10*15)) part of work in 1 day.So whole work will be done in 23.8 days or in 24 days.
• 11 years agoHelpfull: Yes(0) No(1)
• it can't be solved...as data is insufficient.
• 11 years agoHelpfull: Yes(0) No(3)
• 10 m=15 w so
  5m=7.5 w
  now total workers=4w+5m=4w+7.5w=11.5 w
  total work=55*15=825w-days
  so total days required= 825/11.5=71.7 approx 72 days
  
• 11 years agoHelpfull: Yes(0) No(0)