Elitmus
Exam
there is 3 numbers a,b and c in geometric progression such that )(log a + log b +logc)/log 6 =6
how many solution are possible
1 8
2 9
3 35
4 not
Read Solution (Total 1)
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- log(abc)=6log6
so abc=6^6 but in gp ac==b*b=b^2
so b^3=36^3
so b =36 and ac=36*36
so no. of possibles=factors of 36=(1,36),(2,18),(3,12),(4,9)and reverse of these and(6,6)=9. - 11 years agoHelpfull: Yes(5) No(4)
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