if x^y means x raised to the power y. find the last two digits of 2957^3661+3081^3643.

• answer is 98
  2957^3661 ... if we divide 60 by 4 remainder is 1 & hence unit place of 7^1 is 7 ,for the tenth place we shd multiply 5 with 1 hence we get 57 as last two digits.. similarly for 2nd term ie 3081^3643 we get as 41 .... nw add 57+41=98
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• its nt 60 but its 61 which are last two digits of the power 3661
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