(a-5)2+(b-c)2+(c-d)2+(b+c+d-9)2=0

then the value of (a+b+c)(b+c+d) is ?

a)0

b)11

c)33

d)99

• (a-5)2+(b-c)2+(c-d)2+(b+c+d-9)2=0
  => (a-5)2=0,
  (b-c)2=0, (c-d)2=0, (b+c+d-9)2=0
  => a=5,b=c,c=d,b+c-d=9
  => b=c=d and b+c+d=9
  hence b+b+b=9
  => b=3
  so c=d=3
  and we have a=5
  putting all the values in (a+b+c)(b+c+d)
  we get (5+3+3)(3+3+3)=11*9=99
• 10 years agoHelpfull: Yes(1) No(1)