if secA-tanA=3

then find the value of (5cosA+4cotB)??

• we know sec^2A-tan^2A=1 let secA=x tanA=y
  x^2-y^2=1=>(x+y)(x-y)=1 here x-y=3 is given x+y=1/3
  solving equatins we get x=secA=5/3 and y=tanA=4/3
  5cosA=3 4cotA=3
  adding this ans will be 6...
• 11 years agoHelpfull: Yes(1) No(0)