The numbers from 1 to 81 which are exactly divisible by 3 are arranged in ascending order from bottom then which number will be is in 20th position from bottom?

• from 1 to 81 there are 27 no.s which are divisible by 3
  so when arranged in ascending order, they will become an A.P. from bottom to top , so we can use formula (tn= a+(n-1)d)
  so, t20= 3+(20-1)3 => t20= 3+57=60
  thus 20th position from bottom will be number= 60
• 11 years agoHelpfull: Yes(1) No(0)
• from 1 to 81 there are 27 no. which are divisible by 3
  so 20th from bottom or 7th from top = 3*7 = 21
• 11 years agoHelpfull: Yes(0) No(1)
• There are 27 numbers from 3 to 81 when arranging in increasing order.So 20th from bottom is the same as 7th from top. so 7 * 3 = 21.
• 11 years agoHelpfull: Yes(0) No(0)
• There are 27 numbers from 3 to 81 when arranging in increasing order.So 20th from bottom is the same as 7th from top. so 7 * 3 = 21
• 11 years agoHelpfull: Yes(0) No(1)