When numbers are written in base b, we have 12*25=333.The value of b is ?

• (x+2)*(2x+5) = 3x^2+3x+3
  so x = 7;
  
• 11 years agoHelpfull: Yes(11) No(1)
• base=7,let base be b
  (1b+2)(2b+5)=3(b^2)+3b+3
  which on solving will give b=7 & b=-1
  neglecting the -ve part.
• 11 years agoHelpfull: Yes(6) No(0)
• let base=x
  12=>1*x^1+2*x^0=x+2
  25=>2*x^1+5*x^0=2x+5
  333=>3*x^2+3*x^1+3*x^0=3x^2+3x+3
  expression=>12*25=333
  x+2*2x+5=3x^2+3x+3
  after solving we get,
  x=7
  so,b=7
  
• 11 years agoHelpfull: Yes(4) No(0)
• Ans : 7
  let base be b
  12 = (b+2)
  25 = (2b+5)
  333 = 3(b^2+b+1)
  putting in eq 12*25 =333 we get b = 7
• 11 years agoHelpfull: Yes(3) No(1)