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Two people X & Y walk on the wall of a go down in opposite direction. They meet at a point on one side and then go ahead. X after walking for some time, walks in opposite direction for 15 mtrs. Then again he turns back and walks in the original direction. What distance did Y walk before they met again, if X walks 11 mtrs by the time Y walks 8 mtrs.

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ANS:80
X turn back for 15 meters So X was 30 meter behind the Y
they want to be in ratio 11 : 8
by hit and trial 22:16
33:24
44:32
.......
110:80 which have diference 30 meters

so ans is Y travelled 80 meters and X travelled 110 meters .
8 years agoHelpfull: Yes(1) No(0)

What are the dimensions of the room? Like another question posted here, if the room's floor area is 66m x 33m, then, Y must walk for 96 metres before they meet again.
15 years agoHelpfull: Yes(0) No(4)

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