In an exam a student got 20% maximum and fails by 5 marks.another gor 30% and get 20 more than passing marks.the necessary % for passing?

• Let Max marks be x
  then passing marks are .2x+5=.3x-20
  =>x=250
  and passing marks are .2*250+5=55 Answer.
• 11 years agoHelpfull: Yes(3) No(0)
• let the total marks =x
  then pass marks =20% of x +5
  or pass marks = 30% of x -20
  equating above two we get x=250
  and pass marks = 55
  so the required % for passing = 22%
• 11 years agoHelpfull: Yes(2) No(0)
• Ans : 22%
  Lets solve it logically
  the difference in there two condition is 10% of maximum marks and due to this difference cause 25 mark [ in 20% (-5) and in 30% (+20)]
  so 10% of max is 25 => max is 250 and
  so the 5 mark is 2 % of 250
  hence passing % will be (20+2)% = 22%
• 11 years agoHelpfull: Yes(2) No(0)
• let the total marks be Y
  let the passing marks be X
  then from 1st case- 20% of Y=X-5
  or (20/100)Y=X-5 i.e. Y=5X-25
  2nd case- (30/100)Y=X=20
  i.e. 3Y=10X+200
  on solving the above 2 linear equations, we get Y=250 and X=55
• 11 years agoHelpfull: Yes(0) No(0)