Three types of tea the a b c costs Rs 95 kg 100 kg and70 kg respectively How many kgs

ans b)50,25,25 satisfies the condition.
given quantities of b and c are equal .
therefore instead of considering them as a different quantities take average of both and consider it as a single entity .
so the cost of the mixture "D" (equal quantities of "B" and "C") is 170/2=85rs/kg
now the tea contains only "A" of 95 rs/per and "D" of 85 rs/kg.
it is clearly seen that "A" is 5 more and "D" is 5 less than the required cost per kg .
therefore 50/50 will go well .
A=50kg and D=50kg. (D= B&C in equal ratio). therefore B&C=25kg each .
(A:B:C)=(50,25,25)
12 years agoHelpfull: Yes(20) No(2)
option b is correct because 50kg of a 50*95=4750
25kg of b 25*100=2500
25kg of c 25*70=1750
total =9000 which is require price for 100 kg
12 years agoHelpfull: Yes(14) No(3)
here (50*95)+(25*100)+(25*70)=90*100
so ANS is b)50,25,25
12 years agoHelpfull: Yes(6) No(3)
b)50,25,25 satisfies the condition
12 years agoHelpfull: Yes(3) No(4)
total amount will be=9000RS.
b)50,25,25 satisfied the value....
12 years agoHelpfull: Yes(2) No(7)
let the weight of a ,b,c tea be m,n,n kg now we have 2 equations
m+n+n=100
95m=100n=70n=9000
solving these we get m=50

n=25
so answer is( b)
7 years agoHelpfull: Yes(1) No(0)

Three types of tea the a,b,c costs Rs. 95/kg,100/kg and70/kg respectively.How many kgs of each should be blended to produce 100 kg of mixture worth Rs.90/kg, given that the quantities of band c are equal

a)70,15,15 b)50,25,25 c)60,20,20 d)40,30,30