Three types of tea the a,b,c costs Rs. 95/kg,100/kg and70/kg respectively.How many kgs of each should be blended to produce 100 kg of mixture worth Rs.90/kg, given that the quantities of band c are equal

a)70,15,15 b)50,25,25 c)60,20,20 d)40,30,30

• let qty of b and c are x
  then qty of a is 100 - 2x
  cost of each,
  a -> 95(100-2x)
  b -> 100x
  c -> 70*x = 70x
  and total cost of the mixture is 90*100
  therefore
  95(100 -2x) + 100x + 70x = 90*100
  => 9500 - 190x + 170X = 9000
  => 9500 - 9000 = 20x
  => x = 500/20
  => x = 25
  therefore qty of B and C is 25 kg each
  and qty of A is 50 kg (100 - 25 -25)
• 11 years agoHelpfull: Yes(27) No(1)
• ans b)50,25,25 satisfies the condition.
  given quantities of b and c are equal .
  therefore instead of considering them as a different quantities take average of both and consider it as a single entity .
  so the cost of the mixture "D" (equal quantities of "B" and "C") is 170/2=85rs/kg
  now the tea contains only "A" of 95 rs/per and "D" of 85 rs/kg.
  it is clearly seen that "A" is 5 more and "D" is 5 less than the required cost per kg .
  therefore 50/50 will go well .
  A=50kg and D=50kg. (D= B&C in equal ratio). therefore B&C=25kg each .
  (A:B:C)=(50,25,25)
• 13 years agoHelpfull: Yes(20) No(3)
• option b is correct because 50kg of a 50*95=4750
  25kg of b 25*100=2500
  25kg of c 25*70=1750
  total =9000 which is require price for 100 kg
  
• 13 years agoHelpfull: Yes(14) No(3)
• here (50*95)+(25*100)+(25*70)=90*100
  so ANS is b)50,25,25
• 13 years agoHelpfull: Yes(6) No(3)
• b)50,25,25 satisfies the condition
• 13 years agoHelpfull: Yes(3) No(4)
• total amount will be=9000RS.
  b)50,25,25 satisfied the value....
• 13 years agoHelpfull: Yes(2) No(7)
• let the weight of a ,b,c tea be m,n,n kg now we have 2 equations
  m+n+n=100
  95m=100n=70n=9000
  solving these we get m=50
  
  n=25
  so answer is( b)
  
  
• 8 years agoHelpfull: Yes(1) No(0)