the HCF of two positive integers is 5 and their LCM is 105.the numbers are

• HCF * LCM = n1 * n2
  -->
  n1*n2=5*105=525
  so,answer can be: (5 , 105) , (15 , 35)
• 11 years agoHelpfull: Yes(2) No(0)
• HCF * LCM = a * b
  => a*b = 525
  
  => Possible (a , b) = (5 , 105) , (15 , 35)
• 11 years agoHelpfull: Yes(0) No(0)
• In order to have a LCM of 105, the two numbers must only have unique primes that multiply to give 105. 105 is the product of 5, 3 and 7. To have an HCF of 5, the two numbers must only share a factor of 5. Thus the factors of one must be 5 and 3, and the factors of the other must be 5 and 7:
  5x3 = 15
  5x7 = 35
  Therefore the two numbers with an HCF of 2 and an LCM of 30 are 15 and 35.
• 11 years agoHelpfull: Yes(0) No(0)
• ans=>(15,35)&(5,105)3*5,5*7 & 5,3*5*7
  =>15,35 & 5,105
• 11 years agoHelpfull: Yes(0) No(0)
• ans=>(15,35)&(5,105)
  let a and b be the no.
  HCF*LCM=a*b
  =>5*105=a*b
  =525=3*5*5*7
  so with HCF 5, possibilities are,
  =>3*5,5*7 & 5,3*5*7
  =>15,35 & 5,105
• 11 years agoHelpfull: Yes(0) No(0)