There are 6 tasks and 6 persons. Task 1 cannot be assigned either to person 1 or to person 2; task 2 must be assigned to either person 3 or person 4. Every person is to be assigned one task. In how many ways can the assignment be done?

• answer:144
  let task are t1,t2,t3,t4,t5,t6
  person :p1,p2,p3,p4,p5,p6
  t1:p3orp4,p5,p6=3 ways
  t2=p3orp4=2 ways
  t3=rest 4 ways
  t4=3 ways,t5=2 ways,t6=1 ways
  so required ways=3*2*4*3*2*1=144
• 11 years agoHelpfull: Yes(8) No(3)
• 144 ways assignment be done.
  
  Task 2 can be given to two persons only(3 and 4).
  So, Number of ways = 2 ways
  
  First task can be done 3 persons.
  So, Number of ways = 3 ways.
  
  And other tasks can be done in 4 persons.
  So, numbers of ways = 4*3*2*1 = 24 ways
  
  Now, total number of ways = 2*3*24 = 144ways
• 11 years agoHelpfull: Yes(0) No(0)