A Gardener changed his rectangular-shaped garden by increasing its length by 40% and decreasing its width by 20%. The area of the new garden:

a)has increased by 12%
b)cannot be expressed in percentage terms without actual numbers
c)has increased by 8%
d)has increased by 20%

• increase in length =(100+40)%
  decrease in width=(100-20)%
  hense new area =(140*80)=112% =100+12%=12% increase
• 11 years agoHelpfull: Yes(29) No(0)
• ans = d
  if initial area is
  (l*b)=x
  
  then new area is
  (1.4)l (.8)b =(1.12)l*b =1.12x
  increase in area =1.12x - x = 0.12x
  %increas in area
  =100*(0.12x)/x
  =12%
• 11 years agoHelpfull: Yes(3) No(0)
• 40-20-40*20/100= 12% increase
• 11 years agoHelpfull: Yes(3) No(2)
• a)
  ((x+Y)+xy/100).
  take increase in length as x as 40.
  take decrease in width as y as -20.
• 11 years agoHelpfull: Yes(1) No(0)
• the area of the new garden has increased by 12%.initial area-l*b and final area=28l*b/25.so change in area=3l*b/25.therefore,% increase-(3l*b/25/l*b)*100..
  
• 11 years agoHelpfull: Yes(0) No(2)
• d,and overall change is given by the formula a+b+ab/100
  =40-20-80/100=20%
• 11 years agoHelpfull: Yes(0) No(4)