a box contains 5 green, 4 yellow, ans 3 white marbles. three marbles are drawn at random. what is the probability that they are not of same colour?

• First find out the probablity that they all are in the same colour and then remaining we will find by 1-same color probablity..
  here they are in the same colur means (5/12)*(4/11)*(3/10)+(4/12)*(3/11)*(2/10)+(3/12)*(2/11)*(1/10)=3/44 so we got here probablity of having same colour now to find out the remaining that means of having probablity of diffrent colur so just do 1-(3/44) then we will get the answer as 41/44..
• 9 years agoHelpfull: Yes(3) No(1)
• n(S) = ¹²C₃
  n(E) = (⁵C₁ × ⁴C₁ × ³C₁)
  n(E)/n(S) = 3/11
• 11 years agoHelpfull: Yes(2) No(6)
• ANS=3/11 , FOR three different marbels drawn=5C1*4C1*3C1
  FROM total 12 marbels=12C3
  probability of geting 3 marbles of different colour=5C1*4C1*3C1/12C1=3/11
• 11 years agoHelpfull: Yes(2) No(5)