A bag contains 5 Five Rs. coin,8 Eight Rs coin,and 7 Seven Rs coin.If four coins are drawn from the bag at random then find the odds in favor of the draw yielding the maximum possible amount.
A)1:968
B)968:969
C)1:909
D)969:968

• In probability theory and statistics, where the variable p is the probability in favor of a binary event, and the probability against the event is therefore 1-p, "the odds" of the event are the quotient of the two i.e p/(1-p).similrly The odds against the event with probability given as p are (1-p)/p.
  so here in this problem,max amount can be attained only wen all 4 coins are of 8Rs each. where p=the probaility of selecting 4 coins so as to yield max amount among the total possble events.So based on the favourable events possble the value of p=8c4/20c4,which is equal to 14/969.So the odds in favour of getting the max amount =p/(1-p)=(14/969)/(1-(14/969))===14/955(The Ans.)though plzz giv necessry feedbacks 4 my answer..
• 11 years agoHelpfull: Yes(14) No(1)
• total no: of coin=20
  favorable case for yielding max amnt= all 4 coin drawn are rs 8 coin
  
  probability of fav case: 8c4/20c4
  so, odd cases= 1- 8c4/20c4
  ans is: 962:969
• 11 years agoHelpfull: Yes(3) No(9)