A man when he travels at 3 kmph he reaches the station 2 mins late. However when he travels at 4 kmph he reaches 2 mins quick. Find the distance the man has to travel?

• Ans. - 0.8km
  solution - Lets distance = x km
  Accutual Time = y h
  according to first condition
  d=s*t
  x=3*(y+2/60)
  x=3y+1/10
  x-3y=1/10 -------(1)
  according to second condition
  d=s*t
  x=4*(y-2/60)
  x=4y-2/15
  x-4y=-2/15 -------(2)
  eq. first + eq. second
  x-3y =1/10
  x-4y=-2/15
  - + +
  -----------------
  y=1/10+2/15
  y=7/30
  put the value of y in first eq.
  x-3*7/30=1/10
  x=1/10+7/10
  x=0.8
  so, distance = 0.8 km
• 11 years agoHelpfull: Yes(3) No(0)
• 0.8km
  distance=speed*time
  so,d=3*(t+2/60)
  again d=4*(t-2/60)
  solving,t=14/60
  d=48/60=0.8km
• 11 years agoHelpfull: Yes(2) No(0)
• Let the distance is x,& actual time is y..
  when he reach at 3kmph, time is taken (y+2)
  so,x/3=(y+2)........
  when he reach at 4kmph, time is taken (y-2)
  so,x/4=(y-2)........
  By solving two equs, we get x=48 & y=14.
  so, distance = 48 km
  
• 11 years agoHelpfull: Yes(0) No(1)