roy is four years older than erick and 2 years older than iris.if in two years roy will be twice as old as erick then in two years what would be roys age multiplied by iris age

• Ans. 48 years
  Roy = R, Eric = R-4, Iris = R-2
  In 2 years, R+2=2(R-4+2) => R=6
  In 2 years, Roy=6+2=8 and Iris=(6-2)+2=6
  Roy*Iris=8*6=48
  
• 11 years agoHelpfull: Yes(22) No(0)
• let's roy's age be x;erick's age be x-4;iris age be x-2;
  after 2 years, 2(x+2)=2((x-4)+2) => x=6
  present ages are 6,2,4;
  so after 4 (2(condition)+2(after condition)) years,
  ages are 10,6,8 so the product of roy and iris ages are 10*8=80
• 11 years agoHelpfull: Yes(1) No(0)
• ans=48
  r=R,e=R-4,i=R-2
  R+2=2(R-4+2)
  R+2=2R-4
  R=6,e=2,i=4
  after 2 yrs r=6+2=8,i=4+2=6
  r*i=8*6=48
• 11 years agoHelpfull: Yes(1) No(0)
• 80 years
  If Age of Roy=R,Eric=E,Iris=I
  R=E+4,E=R-4 --(i)
  R=I+2 --(ii)
  R+2=2(E+2),R=2E --(iii)
  Substituting value of E from (i) in (iii),R=2(R-4),R=8,so I=8-2=6
  After 2 years multiplication of ages of R & I=(R+2)*(I+2)=10*8=80
  
• 11 years agoHelpfull: Yes(0) No(6)
• Let the ages of roy,erick and iris be r,e,i.
  Given that r=4+e,r=i=2,(r+2)=2(e+2);
  solving third equation r+2=2e+4
  r=2e+2 and we know that r=4+e
  substituting r value in r=2e+2 we get
  4+e=2e+2
  e=2;
  so r=6
  i=4
  after 2 years r becomes 8 and i becomes 6
  so 8*6=48
• 11 years agoHelpfull: Yes(0) No(0)
• roys age=(4/3)iris age
  that means we have to multiply with 4/3 .this is ans..
• 11 years agoHelpfull: Yes(0) No(0)