T E A
H A D
------
L D T R
H R S A *
E W D A * *
--------------
L E S S E R

• 615
  *354
  ------------------
  2460
  3075
  1845
  ------------------
  217710
• 11 years agoHelpfull: Yes(10) No(1)
• A=5 OR 6 SINCE H*A=A SO A=5
  A*D=R SO D WILL BE EVEN NO D=2,4,6,8 SO R=0 AS 5*EVEN NO WILL GIVE UNIT DIGIT 0
  D+S+A=S SO D+A HAS TO GIVE 10 BT SINCE D IS EVEN AND A IS ODD SO THERE WILL BE A CARRY FOR IT TO BE 10 D+A+1=10 AS A=5 SO D WILL BE 4
  TEA*A=HRSA IF E IS EVEN S WILL BE 2 AS THERE IS A CARRY OF 2(5*5=25) AND IF E IS ODD S WILL BE 7
  
  NOW TAKE S=7 L+R+D=S L=2 YOU CAN TAKE S=2 AND CHECK BT IT WILL NOT SATISFY
  
  E+1=L SO E=2
  
  TEA*D=LDTR T15*4=24T0 USE THIS AND YOU WILL GET T=6
  
  TEA*H=EWDA 615*H=1W45 H HAS TO BE ODD
  
  H+W SHOULD BE 11 SO H WILL BE 3 AND W=8
  
  SOLVED!!!!!!!!!!!
  REPLY IF ANY PROBLEM IN SOLUTION
• 11 years agoHelpfull: Yes(5) No(1)
• i m not getting it. plz explain
• 11 years agoHelpfull: Yes(3) No(0)
• http://cryptarithmetic.wordpress.com/2013/01/25/multiplication-problem-1/
  
  Follow this link for better understanding of crypt arithmetic.
• 11 years agoHelpfull: Yes(2) No(3)
• @ arvind
  As u can see A=5, A*D will always have 5 or 0 in units place,
  So R can only be 5 or 0 (bt A=5)
  Therefore R=0...
• 11 years agoHelpfull: Yes(2) No(0)
• 615
  354
  ........
  2460
  3075
  1845
  .........
  217710
• 11 years agoHelpfull: Yes(0) No(2)
• @alok kumar
  from ur explanation, read the second line
  "A*D=R SO D WILL BE EVEN NO"
  A is odd, which is fine, but for D to be even R has to be even.
  what is the logic behind assuming R to be even??
  if any1 undrstood please do explain
• 11 years agoHelpfull: Yes(0) No(0)
• 615*
  354
  ----
  2460
  3075
  1845
  ------
  217710
• 11 years agoHelpfull: Yes(0) No(0)
• 615
  *354
  --------
  2460
  3075-
  1845--
  ---------
  217710
• 10 years agoHelpfull: Yes(0) No(0)