A work has been done by 2 persons in 24min.one of them can do this work a lonely in 40min.how much time required to do the same work for the 2nd person?

• sriram krishnamoorthi
  Mar 30th, 2006
  
  let A does the work in 40 mins (given)
  let B does the work in x mins
  amt of work done by A in 1 min = 1/40
  amt of work done by B in 1 min = 1/x
  amt of work done jointly by both A & B = 1/24
  which implies (1/40)+(1/x) = (1/24)
  on solvin the above eqn. for x we get
  x = 60
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