A certain number of men can finish a piece of work in 10 days. If however there were 10 men less it will take 10 days more for the work to be finished. How many men were there originally?

(a) 110 men (b) 130 men (c) 100 men (d) none of these

• given,
  10*X=Work ---eq(1)where X=mens
  (10+10)*(X-10)=Work--eq(2)
  equating eq(1) and eq(2) we get
  10X=200
  =>X=20
  hence Originally 20 mens are there
  so, answer is option d)none of these
• 13 years agoHelpfull: Yes(35) No(7)
• 20 men
  
  so none of these.
• 13 years agoHelpfull: Yes(16) No(11)
• 20
  10xa=k
  20x(a-10)=k
  10xa = 20x(a-10)
• 9 years agoHelpfull: Yes(3) No(3)
• x men work 10 days
  1 day work of x=x/10
  x-10 men work for more than 10 days(ie.10+10=20 days)= x-10/20
  x/10=x-10/20
  20x=10x-100
  and x = 10. Therefore x+10 = 20.
  ans is d
• 10 years agoHelpfull: Yes(0) No(3)
• suppose there are X men
  X men 10 days=1 work
  1 man 1 day=1/(x*10)work.....eq 1
  x-10 men 20 days=same work
  1 man 1 day=1/(20*(x-20))work.....eq 2
  eq1=eq2
  we will get x=100 so option c is right
• 10 years agoHelpfull: Yes(0) No(7)
• Let no. Of men be X
  Work done by X men X*10
  Work done by X-10 men will be (X-10)*20
  20 coz 10 more days than 10days
  X*10=(X-10)*20
  X=20
  D opt none of these
• 7 years agoHelpfull: Yes(0) No(0)