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The population of a city increases @ 4% p.a. There is an additional annual increase of 4% of the population due to the influx of job seekers, find the % increase in population after 2 years ?
Read Solution (Total 9)
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- Say you start with P people. In 1 year you have 1.08P people. In 2 years
there are 1.08(1.08P) people = 1.1664P people.
The increase is 1.1664P-P = 0.1664P
The rate of increase = 0.1664P/P=.1664 = 16.64% - 9 years agoHelpfull: Yes(15) No(0)
- total annual increament in population = 4+4 = 8%
let the population be x
Population after 2 years = 1.08x +.0864x
Population increase = 1.08x + .0864x - x
%increase = ((1.08x + .0864x - x)/x )*100
= ( 1.08 + .0864 - 1 )*100
=.1664*100
=16.64% - 11 years agoHelpfull: Yes(13) No(1)
- 1 year increment =4+4=8%
required %increment= 8+8+8*8/100 =16.64% - 8 years agoHelpfull: Yes(9) No(0)
- let population now be 100
as given population increased 4% p.a.
therefore population will be 104 after one year
and also given additional increment in population due to job seekers is 4%
therefore population will be =104+104X0.04
=104+4.16
=108.16
after one year, population is 108 (4% + 4%)
after 2 years, population is (.04*108.16)+108.16 = 112.4864
due to job seekers population will be after two years=116.986256
increase in population = 116.986256 - 100 = 16.986256
% increase = (16.986256/100) * 100 = 116.986256%
- 11 years agoHelpfull: Yes(8) No(10)
- so for a total 8% p.a the population increases
so 16% increase after the 2 years - 13 years agoHelpfull: Yes(7) No(13)
- let the population be x.... (x(1+ 8/100)^2 - x)/x *100 =16.64%
- 10 years agoHelpfull: Yes(2) No(1)
- 4%+4%=8% for 1 year
so % increases after 2 years 2*8 =16% - 8 years agoHelpfull: Yes(0) No(2)
- use effective percentage formula....
per year population is increasing 4%+4% = 8%
1year 2year
8% 8%
effective % = 8 + 8 + 8*8/100
= 16+64/100
= 16.64% - 7 years agoHelpfull: Yes(0) No(1)
- simply, apply
a+b+(a*b)/100
where, a=b=8(total percent of increase of population p.a) - 6 years agoHelpfull: Yes(0) No(0)
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