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Time and Work
15 men take 21 days of 8 hrs. each to do a piece of work. How many days of 6 hrs. each would it take for 21 women if 3 women do as much work as 2 men?
(a) 30 (b) 20 (c) 19 (d) 29
Read Solution (Total 2)
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- Let 1Man does 1unit/hr of work
15M in 21 days of 8hrs will do (15*21*8) units
3W = 2M
1W=(2/3)units/hr
21W with 6hrs a day will take (15*21*8)/(21*6*(2/3)) days
=> 30 Days
ANSWER => (a) - 12 years agoHelpfull: Yes(24) No(1)
- work done by 1 men in one hour = 1/(15*21*8)
work done by 2 men in one hour = 2/(15*21*8)
work done by 3 women = work done by 2 men in one hour = 2/(15*21*8)
work done by 21(7*3) women in one hour = 7* (work done by 3 women) = 1/180
work done by 21(7*3) women in six hour = 6/180 = 30 days
- 8 years agoHelpfull: Yes(2) No(1)
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