Q. City B is 8 miles east of City A. City C is 6 miles north of City B. City D is 16 miles east of city C. City E is north of City D by 12 miles. What is the shortest distance from City A to City E

• 30.
  square root of 8 and 6 plus square root of 16 and 12
  
• 8 years agoHelpfull: Yes(1) No(0)
• B is at the origin (0,0)
  A is at (8,0)
  C is at (0, 10)
  D is at (13, 10)
  E is at (13, 12)
  
  So from (8,0) to (13,12)
  use the Pythagorean theorem or the distance formula
  horizontal distance is 13 - 8 = 5
  vertical distance is 12 - 0 = 12
  5^2 + 12^2 = x^2
  this is a Pythagorean triple 5 - 12 - 13 (feel free to solve it instead)
  you get x = 13
  
  A and E are 13 miles apart
  
• 8 years agoHelpfull: Yes(0) No(0)