Q. If the ratios of speed of A and B is 4:5 and A takes 20 minutes more than B to cover the distance then how much time does A take?

• speed is inversely proportional to time i.e s1/s2=t2/t1
  here given s1/s2=4/5
  here also given A takes 20 mins more than B
  assume B takes x mins,den A ll take (x+20) mins
  so s1/s2=t2/t1
  4/5=x/(x+20)
  4x+80=5x
  x=80
  therefore B takes 80 mins & A take (x+20) i.e 80+20=100 mins
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