A started at 9.00 am with 6 mph and B started at 9.30 am with 8mph in the same direction. At what time they will meet..

• A's speed=6mph ,B's speed=8mph
  Let,after x hrs they will meet..
  so,the distance traveled by A in x hrs should be same the distance traveled by B in (x-1/2)hrs [as B started journey after 30 min of A]
  Thus, 6x=8(x-1/2)[as distance=speed*time]
  =>8x-6x=4
  =>2x=4
  =>x=2
  after 2 hrs they will meet so time=(9+2)=11.00a.m
• 10 years agoHelpfull: Yes(66) No(1)
• A covers 6 miles in 1 hour.so,at 9.30am it has already covered 3 miles.
  suppose, after t hours they will meet.
  then, equating the distances covered by them, 6t+3=8t
  or, t= 1 hr 30 min.
  they will meet at 11.00 am.
• 10 years agoHelpfull: Yes(20) No(1)
• time A B
  speed speed
  9.00 0 0
  9.30 3 0
  10.0 6 4
  10.30 9 8
  11.00 12 12
  
  so they will meet at 11.00 a.m
• 10 years agoHelpfull: Yes(15) No(1)
• A started at 9 a.m and B at 9. 30. So lets take in things in relative to A,since started the race earlier. After 1 hour(i.e at 10 a.m) A will travel 6 m and B will travel 4 m. Again afer half an hour(i.e at 10 30 a.m) A will travel 9 m and B 8m. Finally at 11 a.m (i.e 2 hours from when A have started),both will travel 12m.Hence meeting after 2 hours.
• 10 years agoHelpfull: Yes(3) No(0)
• Since A start at 9 AM with 6mph for 1 hr=6m Similarly B at 9.30 AM for 1hr=8m
  Initially A and B travel 6m & 8m so they wont meet their timings wil be 10 AM and 10.30 AM
  For the second hr A 11 AM b at 11.30 AM but inbetween they wil meet since 12m wil be travelled by both
• 10 years agoHelpfull: Yes(1) No(0)
• think this problem as train problem moving in same directions with different speed
  ....then by formula a-b=8-6=2 ....like this....
• 10 years agoHelpfull: Yes(1) No(2)
• Da=Sa*Ta=6*x
  Db=Sb*Tb=8*(x-1/2)
  distance is at the same point so 6x=8*(x-1/2)
  x=2hrs so meeting time is 9:00+2:00 = 11:00 a.m
• 10 years agoHelpfull: Yes(1) No(0)
• A B
  9:00 0 0
  9:30 3 0 -->(6mph so for 30 min = 3miles)
  10:00 6 4
  10:30 9 8
  11:00 12 12
  
  so they meet at 11:00 am
• 9 years agoHelpfull: Yes(1) No(0)
• guys plsss send me cts placement papers... also giv me details of an OFF-campus.. wat r al the portions?how many rounds..lik al these stuffs...
• 10 years agoHelpfull: Yes(0) No(8)
• (x+3)/8 = x/6
  x = 9 mile
  time = 9/6 = 1hr 30mins
  Actual time = 11a.m
• 10 years agoHelpfull: Yes(0) No(1)
• Let it take x hrs from 9:30 where they both meet.
  Till 9:30 A has already traveled 3 miles .
  So in next x hrs A will travel 6x miles and B will travel 8x miles.
  so the distance they both travel becomes equal.
  Equation-> 3+6x=8x
  2x=3
  x=1.5hr
  hence from 9:30 add 1.5 hr
  we get 11 am
• 7 years agoHelpfull: Yes(0) No(0)