5 men or 8 women do equal amount of work in a day. a job requires 3 men and 5 women to finish the job in 10 days how many woman are required to finish the job in 14 days.
a) 10 b) 7 c) 6 d) 12

• Lets assume total LCM(5,8) = 40units.
  As, 5 men or 8 women do equal amount of work in a day,
  1Man does 8units/day and 1Woman does 5units/day.
  3M and 5W in 10 days do (3*8 + 5*5)*10 = 490units
  To do 490 units in 14 days, number of Women required = 490/(14*5) = 7
  ANSWER => (b)
• 12 years agoHelpfull: Yes(30) No(5)
• 1 man can do the work of 8/5 = 1.6 women
  
  equivalent of 3*1.6 + 5 = 9.8 women take 10 days
  
  so women needed to do the work in 14 days
  
  = [10/14]*9.8
  
  = 7
• 10 years agoHelpfull: Yes(12) No(3)
• 5 men= 8 women
  1 men=8/5 w
  given that (3m+5w)10=X*14
  3*8/5w+5w=X*14
  x=7w
  
• 7 years agoHelpfull: Yes(2) No(0)
• 5=10
  x=14
  10x=70
  x=7
• 7 years agoHelpfull: Yes(1) No(0)