A boy has Rs 2. He wins or loses Re 1 at a time If he wins he gets Re 1 and if he loses the game he loses Re 1.He can loose only 5 times. He is out of the game if he earns Rs 5.Find the number of ways in which this is possible?

• 16 ways are possible.
• 12 years agoHelpfull: Yes(22) No(19)
• He has 2Rs.He wins or loses Re 1 at a time.
  for 1Rs.He may have different probabilities as (WW,WL,LW,LL)i.e,for one rupee he has 8chances in the same way for another one rupee he has another 8 chances .
  So,total number of chances/ways are 16.
  /*If he looses 4times one rupee will be lossed and if he had another loss he is out of game*/
• 10 years agoHelpfull: Yes(22) No(6)
• how dipin???
  pls xplain....
• 12 years agoHelpfull: Yes(12) No(3)
• no lose ( 1 way)
  one lose + four wins(3 ways)
  twoloses+5 wins(7 ways)
  three loses+6 wins( 21 ways)
  four loses+ 7 wins(49 ways)
  five loses he is out of the game
  total ways = 1+3+7+21+49 = 81
• 9 years agoHelpfull: Yes(0) No(10)
• Dipin Plz explain
• 8 years agoHelpfull: Yes(0) No(0)
• please explain the answer in detail
• 8 years agoHelpfull: Yes(0) No(0)
• 0L -> 1 way
  1L -> 3 ways
  2L -> 7 ways
  3L -> 4 ways
  4L -> 1 way
  total 16 ways
• 7 years agoHelpfull: Yes(0) No(1)