What is the remainder when 91+92+93+....+98 is divided by 6?

• We will individually divide the numbers and then after summing up all the individual remainders we will divide the sum to get the ultimate result i.e. remainder
  
  So 1st 91 is divided by 6 and the remainder is 1 because 6*15=90
  Similarly, in 92 remainder will be one more which is 2
  Similarly, 93 = 3, 94 = 4, 95 = 5, 96 = 0, 97 = 1, 98 = 2.
  So the ultimate the sum = 18
  And finally the remainder = 0(bcz 18 % 6 = 0)
  
  
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