How many squares with sides 1/2 inch long are needed to cover a rectangle that is 4 ft long and 6 ft wide

(a) 24 (b) 96 (c) 3456 (d) 13824 (e) 14266

• t takes four of those little squares -- each one 1/2 inch on a side -- to cover one square inch. That's because each one is 1/2 x 1/2, or 1/4 of a square inch.
  
  In a rectangle that is 48 inches by 72 inches, there are 3456 square inches.
  
  Since it takes 4 little squares to cover each of those inches, then it would need 3456 x 4 squares (1/2 inch on a side each) to cover a rectangle 4 feet by 6 feet.
  
  That is 13,824 of those squares.
• 11 years agoHelpfull: Yes(7) No(0)
• area of square= a^2
  area of rectangle=l*b
  let n be the number of squares required
  therefore, n*(1/2)*(1/2)=48*72 ( 1ft=12 inches)
  n=13824 i.e option D
• 8 years agoHelpfull: Yes(2) No(0)
• 1 foot =12 inches.
  6 squares of 1/2 inch can be formed in 1feet hence 6*4=24 can be formed in 4 feet.
  option A
• 13 years agoHelpfull: Yes(1) No(24)
• area of rectangle=l*b
  =4*6=24
  24sq.ft=24*12*12nches=3456sq.inches
  area of one square piece=side*side=1/2*1/2=1/4
  
  squares needed=3456/1/4=3456*4=13824
• 7 years agoHelpfull: Yes(0) No(0)