The petrol tank of an automobile can hold g liters.If a liters was removed when the tank was full, what part of the full tank was removed?

(a)g-a (b)g/a (c) a/g (d) (g-a)/a (e) (g-a)/g

• (c) a/g
  
  removed Qty in litres/full capacity in litres = a/g
• 13 years agoHelpfull: Yes(19) No(1)
• ans: c)a/g
  
  >>imagine g=100 litrs and a=30 litrs that was removed
  
  >> Hence the "part of the full tank was removed" = a/g = 30/100
• 10 years agoHelpfull: Yes(6) No(1)
• g-a/g because g=full tank and a=remove liter there4 g/g-a/g=g-a/g
• 13 years agoHelpfull: Yes(5) No(2)
• ans is g-a/a
• 13 years agoHelpfull: Yes(4) No(3)
• (g-a)/g
  
  g is full &a is removed .so remaining portion/total
• 10 years agoHelpfull: Yes(2) No(1)
• (g-a) /g
  Reason is
  Total g liters after removing a liters
  Tank capacity is full that means we have to do
  g-m.
  Now to find it's percent in total i.e
  (g-a) /g
• 5 years agoHelpfull: Yes(0) No(0)