It was calculated that 75 men could complete a piece of work in 20 days. When work was scheduled to commence, it was found necessary to send 25 men to another project. How much longer will it take to complete the work?

• Total mandays reqd= 75*20
  when only 50 men are left,
  days reqd to complete project by 50 men = 75*20/50 = 30 days
  
  so additional days = 30-20=10 days.
• 12 years agoHelpfull: Yes(24) No(3)
• Answer:
  30 days.
  
  Explanation:
  Before:
  One day work = 1 / 20
  One man’s one day work = 1 / ( 20 * 75)
  Now:
  No. Of workers = 50
  One day work = 50 * 1 / ( 20 * 75)
  
  The total no. of days required to complete the work = (75 * 20) / 50 = 30
• 10 years agoHelpfull: Yes(7) No(2)
• 75 MEN = 20 DAYS
  
  50 MEN = 75 /50 x 20 = 3/2 x 20 = 30 DAYS
  
  answer = 10 days longer
• 9 years agoHelpfull: Yes(3) No(1)
• for 75 students 20 days
  so, for 25 members 60 days
  so, for 50... 30 days.
• 12 years agoHelpfull: Yes(2) No(5)
• time take to complete the work is 27.2 days
• 12 years agoHelpfull: Yes(1) No(6)
• fr 950gm...........rs10(say)
  fr 1000gm..........rs10.52
  so, .52/10*100=5.2%
• 12 years agoHelpfull: Yes(1) No(5)
• (75*20)/(75-25)= 30 days
  
  answer is 10 days longer
• 7 years agoHelpfull: Yes(0) No(0)
• men days
  75 20
  50 x
  
  x=(75 * 20)/50 = 30
• 7 years agoHelpfull: Yes(0) No(0)
• 1 men 1 day can complete the 1/75*20th part, so so 50 men can complete 1 part in 75*20/50=30 days so 10 more days required
• 7 years agoHelpfull: Yes(0) No(0)
• 75 men ====20 d
  1 men=====20*75=1500days===1500units work
  so 1500/50=30 days
• 7 years agoHelpfull: Yes(0) No(0)