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Maths Puzzle
Abhishek had a certain number of Re1 coins, Rs 2 coins and Rs 10 coins. If the number of Re 1 coins he had is six times the number of Rs 2 coins Abhishek had, and the total worth of his coins is Rs 160, find the maximum number of Rs 10 coins Abhishek could have had
Read Solution (Total 1)
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- If the Abhishek had x Re 1, y Rs 2 coins and z Rs 10 coins, the total value of coins he had:
=x(1)+y(2)+z(10)=x+2y+10z=160
Since, 6y=x
Thus, 8y+10z=160 i.e 8y is a multiple of 10 i.e. y=5 or y=10
i.e. (x,y,z)=(30,5,12) or (60,10,18)
Thus, the maximum value of 'z' is 12 - 6 years agoHelpfull: Yes(0) No(0)
self Other Question
The total age of some 7 years old and some 5 years old children is 60 years. If I have to select a team from these children such that their total age is 48 years, In how many ways can it be done?
A.
3
B.
2
C.
1
D.
4
In a family of husband, wife and a daughter, the sum of the husband’s age, twice the wife’s age, and thrice the daughter’s age is 85; while the sum of twice the husband’s age, four times the wife’s age, and six times the daughter’s age is 170. It is also given that the sum of five times the husband’s age, ten times the wife’s age and fifteen times the daughter’s age equals 450. The number of possible solutions, in terms of the ages of the husband, wife and the daughter, to this problem is