A man was engaged on a job for 30 days on the condition that he would get a wage of Rs. 10 for the day he works, but he have to pay a fine of Rs. 2 for each day of his absence. If he gets Rs. 216 at the end, he was absent for work for ... days

• let he haven't work for x day
  then (30 -x)*10-2*x=216
  ==> 300 -12x=216
  12x=84
  ==> x=7
• 11 years agoHelpfull: Yes(12) No(0)
• he worked for 23 days and he was absent for 7 days . so his fine is 14 and the wage is 230. 230-14= 216
• 12 years agoHelpfull: Yes(4) No(2)
• 30 days X 10 = 300
  he get = 216
  loss = 300-216 = 84
  per day absent means = 12Rs loss
  84/12 = 7 days
  
• 8 years agoHelpfull: Yes(4) No(0)
• When the man absent he doesn't get 10rupees besides he has to give fine 2rupee.so total 12rupee... So days he absent=300-216/12=7days
• 8 years agoHelpfull: Yes(2) No(0)
• take x as the working day y as the absent day
  x=30-y---------eq(1)
  10x-2y=216-----eq(2)
  solving eq(1) and eq(2) we get
  y=8.4
  x=21.6
  so x work for 21.6 days and absent for 8.4days
• 12 years agoHelpfull: Yes(1) No(4)
• 10x-2(30-x)=216
  x=23
• 8 years agoHelpfull: Yes(0) No(0)
• Ans - 23day
  let assume man worked x days
  so he was absent (30-x) days
  equation - {10*x + (30-x)*(-2)}= 216
  =>x=23;(ans)
• 7 years agoHelpfull: Yes(0) No(0)
• Let he work for X days then he was absent for (30 -X) days.
  Total Paid = Rs. 216
  Now according to question,
  10 *X - 2*(30 -X) = 216
  10X - 60 +2X = 216
  12X = 276.
  X = 23 days.
  No. of working days = 23, therefore
  No. of absent = 30 -X = 30 - 23 = 7 days
• 6 years agoHelpfull: Yes(0) No(0)
• 216/30=7.2 where he is absent for 7 days with 2/- fine(remainder) per day
• 6 years agoHelpfull: Yes(0) No(0)