A man bought a horse and a cart. If he sold the horse at 10 % loss and the cart at 20 % gain, he would not lose anything; but if he sold the horse at 5% loss and the cart at 5% gain, he would lose Rs. 10 in the bargain. The amount paid by him was Rs.­­­­_______ for the horse and Rs.________ for the cart

• let cp of horse be x
  and cp of cart be y
  then
  horse sp=90*x/100=9x/10
  cart sp=120*y/100=6y/5
  now he say thru these no loss no gain mean cp of both equal to sp of both
  => x+y=(9x/10)+(6y/5)-----(1)
  again
  horse sp=95*x/100=19x/20
  cart sp=105*y/100=21y/20
  now at this time he suffer loss of 10 rs mean
  cp=sp+10
  x+y=19x/20+21y/20+10-----(2)
  solving eq 1 and 2 u will get the ans x=400 & y=200
• 12 years agoHelpfull: Yes(14) No(4)
• Let the cost price of horse be 'x'
  Let the cost price of cart be 'y'
  Case 1: 10% loss in horse = 0.1x
  20% gain in cart = 0.2y
  Since they are equal, 0.1x=0.2y or x=2y or x-2y=0 ................(1)
  Case 2: 5% loss in horse = 0.05x
  5% gain in cart = 0.05y
  0.05x=0.05y+10 or 5x=5y+1000 or 5x-5y=1000 .................(2)
  On solving (1) and (2) we get y=200 & x=400
• 7 years agoHelpfull: Yes(2) No(0)