Two alloys A and B are composed of two basic elements. The ratios of the compositions of the two basic elements in the two alloys are 5:3 and 1:2, respectively. A new alloy X is formed by mixing the two alloys A and B in the ratio 4:3. What is the ratio of the composition of the two basic elements in alloy X?

• Let the actual amount of A be 4x and actual amount of B be 3x since A and B are in the ratio 4/3
  
  amount of first basic element in the new alloy T (5/8)*4x + (1/3)*3x = (7x)/2
  
  amount of second basic element in the new alloy T (3/8)*4x + (2/3)*3x= (7x)/2
  
  so ratio of first basic element to second basic element: [(7x)/2 ] / [ 7x/2] = 1/1 = 1:1 ( Answer A)
• 9 years agoHelpfull: Yes(27) No(2)
• A B
  5/8 1/3
  /
  X
  /
  x-1/3 5/8-x
  
  (x-1/3)/(5/8-x)=4/3
  
  x=0.5
  
  so the ans is 1:1
• 11 years agoHelpfull: Yes(11) No(10)
• A is 5:3
  B is 1:2
  A+B= (5+1):(3+2)=6:5------------(1)
  total=4:3-----------------------------(2)
  subtract (1)-(2)
  =2:2
  so ans is 1:1
• 7 years agoHelpfull: Yes(7) No(0)
• A is 5:3
  B is 1:2
  So in the mixture (5x+x)/(3x+2x)=4/3
  solving x and y
  x=2/3
  y=4/5
  ==> x:y=5:6
• 11 years agoHelpfull: Yes(0) No(17)