Two taps can fill a tank in 12 min and 18 min respectively. Both the taps are kept open for 2 min and then the tap that fills the tank in 12 min is turned off. In how many more minutes will the tank be filled?

A.

9

B.

12

C.

13

D.

10

• C. 13
  If Tap A fills tank completely in 12 min. & Tap B in 18 18 min.,then
  Tap (A+B)in 2 min=2[1/12 + 1/18]=2*5/36=5/18,
  Remaining tank=13/18, to be filled by Tap B
  So min. required=(13/18)/(1/18)=13
• 11 years agoHelpfull: Yes(1) No(0)