If A speaks the truth 80% of the times, B speaks the truth 60% of the times. What is the probability that they tell the truth at the same time

(a) 0.8
(b) 0.48
(c) 0.6
(d) 0.14

• probability that A speaks truth is 80/100=0.8 probability that B speaks truth is 60/100=0.6 since both A and B are independent of each other so PROBABILITY OF A INTERSECTION B = P(A) *P(B) =0.8 * 0.6 = 0.48
• 13 years agoHelpfull: Yes(63) No(2)
• 80/100 * 60/100
  = .48
• 13 years agoHelpfull: Yes(17) No(4)
• p(A)=80% i.e. 4/5
  p(B)=60% i.e. 3/5
  both the events are independent
  p(A n B) = p(A) *p(B) = 4/5*3/5 = 12/25
  ie 48% or 0.48
• 6 years agoHelpfull: Yes(1) No(0)
• 0.8*0.6=.48
• 9 years agoHelpfull: Yes(0) No(0)
• ans. is 0.48
  
• 9 years agoHelpfull: Yes(0) No(0)
• Probability of A, speaking the truth, P(A)=80 %
  =80/100 = 4/5
  
  Probability of B, speaking the truth, P(cool.gif=60 %
  =60/100 = 3/5
  
  
  the probability that they tell the truth at the same time is
  = P(A) * P(cool.gif
  = 4/5 * 3/5
  = 12/25
  = 0.48
• 6 Months agoHelpfull: Yes(0) No(0)