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Maths Puzzle
On a ABC, on side AB 5 points are marked, on side BC 4 points are marked, while on side AC 3 points are such that none of the points thus marked are on the vertex, then how many triangles can be drawn by joining these points?
Read Solution (Total 1)
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- ncr=12c3 12*11*10/3*2*1
- 8 years agoHelpfull: Yes(0) No(0)
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