a,b,c,d and e are five natural numbers. Find the number of ordered sets (a,b,c,d,e) possible such that a+b+c+d+e=64.

A.

64C5

B.

63C4

C.

65C4

D.

63C5

• Let assume that there are 64 identical balls which are to be arranged in 5 different compartments (Since a,b,c,d,e are distinguishable) If the balls are arranged in a row
  i.e., o,o,o,o,o,o......(64 balls)
  
  We have 63 gaps where we can place a wall in each gap, since we need 5 compartments we need to place only 4 walls.
  We can do this in 63C4 ways
• 10 years agoHelpfull: Yes(0) No(2)