While packing for a business trip Mr. Debashis has packed 3 pairs of shoes, 4 pants, 3 half-pants,6 shirts, 3 sweater and 2 jackets. The outfit is defined as consisting of a pair of shoes, a choice of "lower wear" (either a pant or a half-pant), a choice of "upper wear" (it could be a shirt or a sweater or both) and finally he may or may not choose to wear a jacket. How many different outfits are possible?

A.

567

B.

1821

C.

743

D.

1701

• Number of ways a pair of shoes can be selected =3C1=3 ways.
  Number of ways "lower wear" can be selected =(3+4)=7 ways
  Number of ways "upper wear" can be selected =3+6+3×6=27 ways
  Number of ways jacket can be chosen or not chosen = 3 ways {No jacket, 1st jacket, 2nd jacket)
  
  ⇒ Total number of different outfits =3×7×27×3= 1701 ways.
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