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Maths Puzzle
A woman took a certain number of eggs to the market and sold some of them. A next day, through the industry of her hens, the number left over had been doubled, and she sold the same number as the previous day.
On the third day the new remainder was tripled, and she sold the same number as before.
On the fourth day the remainder was quadrupled, and her sales were the same as before.
On the fifth day what had been left over were quintupled, yet she sold exactly the same as on all the previous occasions and so disposed of her entire stock.
(i) What is the smallest number of eggs she could have taken to market the first day?
(ii) How many did she sell daily? (The answer is not zero).
Read Solution (Total 1)
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- First day she took 103 and sold 60 for each days
1day---103-60=43
2daay--43*2-60=26
3day---3*26-60=18
4day---4*18-60=12
5day---5*12-60=0 - 5 years agoHelpfull: Yes(0) No(0)
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